Optimal. Leaf size=102 \[ -\frac{4 e^2 \sqrt{\sin (c+d x)} \text{EllipticF}\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right ),2\right )}{3 a d \sqrt{e \sin (c+d x)}}+\frac{2 e \sqrt{e \sin (c+d x)}}{a d}-\frac{2 e \cos (c+d x) \sqrt{e \sin (c+d x)}}{3 a d} \]
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Rubi [A] time = 0.222465, antiderivative size = 102, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28, Rules used = {3872, 2839, 2564, 30, 2569, 2642, 2641} \[ -\frac{4 e^2 \sqrt{\sin (c+d x)} F\left (\left .\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )\right |2\right )}{3 a d \sqrt{e \sin (c+d x)}}+\frac{2 e \sqrt{e \sin (c+d x)}}{a d}-\frac{2 e \cos (c+d x) \sqrt{e \sin (c+d x)}}{3 a d} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2839
Rule 2564
Rule 30
Rule 2569
Rule 2642
Rule 2641
Rubi steps
\begin{align*} \int \frac{(e \sin (c+d x))^{3/2}}{a+a \sec (c+d x)} \, dx &=-\int \frac{\cos (c+d x) (e \sin (c+d x))^{3/2}}{-a-a \cos (c+d x)} \, dx\\ &=\frac{e^2 \int \frac{\cos (c+d x)}{\sqrt{e \sin (c+d x)}} \, dx}{a}-\frac{e^2 \int \frac{\cos ^2(c+d x)}{\sqrt{e \sin (c+d x)}} \, dx}{a}\\ &=-\frac{2 e \cos (c+d x) \sqrt{e \sin (c+d x)}}{3 a d}+\frac{e \operatorname{Subst}\left (\int \frac{1}{\sqrt{x}} \, dx,x,e \sin (c+d x)\right )}{a d}-\frac{\left (2 e^2\right ) \int \frac{1}{\sqrt{e \sin (c+d x)}} \, dx}{3 a}\\ &=\frac{2 e \sqrt{e \sin (c+d x)}}{a d}-\frac{2 e \cos (c+d x) \sqrt{e \sin (c+d x)}}{3 a d}-\frac{\left (2 e^2 \sqrt{\sin (c+d x)}\right ) \int \frac{1}{\sqrt{\sin (c+d x)}} \, dx}{3 a \sqrt{e \sin (c+d x)}}\\ &=-\frac{4 e^2 F\left (\left .\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )\right |2\right ) \sqrt{\sin (c+d x)}}{3 a d \sqrt{e \sin (c+d x)}}+\frac{2 e \sqrt{e \sin (c+d x)}}{a d}-\frac{2 e \cos (c+d x) \sqrt{e \sin (c+d x)}}{3 a d}\\ \end{align*}
Mathematica [A] time = 19.8295, size = 69, normalized size = 0.68 \[ -\frac{2 (e \sin (c+d x))^{3/2} \left (\sqrt{\sin (c+d x)} (\cos (c+d x)-3)-2 \text{EllipticF}\left (\frac{1}{4} (-2 c-2 d x+\pi ),2\right )\right )}{3 a d \sin ^{\frac{3}{2}}(c+d x)} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.348, size = 112, normalized size = 1.1 \begin{align*}{\frac{2\,{e}^{2}}{3\,a\cos \left ( dx+c \right ) d} \left ( \sqrt{-\sin \left ( dx+c \right ) +1}\sqrt{2+2\,\sin \left ( dx+c \right ) }\sqrt{\sin \left ( dx+c \right ) }{\it EllipticF} \left ( \sqrt{-\sin \left ( dx+c \right ) +1},{\frac{\sqrt{2}}{2}} \right ) - \left ( \cos \left ( dx+c \right ) \right ) ^{2}\sin \left ( dx+c \right ) +3\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ){\frac{1}{\sqrt{e\sin \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \sin \left (d x + c\right )\right )^{\frac{3}{2}}}{a \sec \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{e \sin \left (d x + c\right )} e \sin \left (d x + c\right )}{a \sec \left (d x + c\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \sin \left (d x + c\right )\right )^{\frac{3}{2}}}{a \sec \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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